Rafael on Nostr: n+1 pieces, each divided into (n+1)² pieces gives me (n+1)(n+1)² or (n+1)³ pieces. ...
n+1 pieces, each divided into (n+1)² pieces gives me (n+1)(n+1)² or (n+1)³ pieces. Maybe you're starting to see a pattern here? 1 dimensional tomato can be cut into (n+1)¹ pieces, 2d tomato into (n+1)², 3d into (n+1)³ and so on. If you want, it's possible to prove mathematically that this relationship continues for as many dimensions as you want. But for now you can rest easy knowing that if you ever get a fifth dimensional tomato, it'll chop into (n+1)⁵ pieces. 😁6/6
Published at
2023-12-07 16:24:18Event JSON
{
"id": "aaa86ff5e52556b5d15d398a8073df609b5624a616defd9077610f4b078a7f54",
"pubkey": "294f2bcc92b7c772f04953312f33cfce650d500805de52b4ff4ba40e47e57fe1",
"created_at": 1701966258,
"kind": 1,
"tags": [
[
"e",
"52e0e5efe9ba64c49f2916ac3f94285ff128c75f69c235e3ed1f07ff52a869ee",
"wss://relay.mostr.pub",
"reply"
],
[
"proxy",
"https://mastodon.sdf.org/users/ipxfong/statuses/111540060727177467",
"activitypub"
]
],
"content": "n+1 pieces, each divided into (n+1)² pieces gives me (n+1)(n+1)² or (n+1)³ pieces. Maybe you're starting to see a pattern here? 1 dimensional tomato can be cut into (n+1)¹ pieces, 2d tomato into (n+1)², 3d into (n+1)³ and so on. If you want, it's possible to prove mathematically that this relationship continues for as many dimensions as you want. But for now you can rest easy knowing that if you ever get a fifth dimensional tomato, it'll chop into (n+1)⁵ pieces. 😁6/6",
"sig": "6d56428ce2f8fbee3f5c9c36ecec62583850614b8343cc1e5b13e0f77d6ab97aca7307778e37979b9ff138f83799bbe06aec299a9dcbd4fc25f2a705fdc3e295"
}
