📅 Original date posted:2021-01-12
📝 Original message:
Lloyd Fournier <lloyd.fourn at gmail.com> writes:
> Rusty, Zman,
>
> A concern I have with only doing one signaling transaction out of the whole
> group of inputs is that it means you don't prove ownership of the other
> inputs.
But that's by design. You can contact two peers and middleman between
them to produce a single tx.
The practical problem with a signalling tx is that it's hard to tell if
it's conflicting. Mallory uses a single UTXO to probe for everyone's
UTXO at once. Poor Bob wants to both wait 60 seconds to see if a
conflicting tx ends up in his mempool, *and* broadcast it ASAP to signal
to others. He wants to do both of these *before* revealing his own
UTXOs.
Not sure how to square this, but I do prefer this approach over PoDLE.
Cheers,
Rusty.
Rusty Russell [ARCHIVE] /
npub1zw…hkhpx
2023-06-09 13:01:50
in reply to nevent1q…d308
Author Public Key
npub1zw7cc8z78v6s3grujfvcv3ckpvg6kr0w7nz9yzvwyglyg0qu5sjsqhkhpxPublished at
2023-06-09 13:01:50Event JSON
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"content": "📅 Original date posted:2021-01-12\n📝 Original message:\nLloyd Fournier \u003clloyd.fourn at gmail.com\u003e writes:\n\u003e Rusty, Zman,\n\u003e\n\u003e A concern I have with only doing one signaling transaction out of the whole\n\u003e group of inputs is that it means you don't prove ownership of the other\n\u003e inputs.\n\nBut that's by design. You can contact two peers and middleman between\nthem to produce a single tx.\n\nThe practical problem with a signalling tx is that it's hard to tell if\nit's conflicting. Mallory uses a single UTXO to probe for everyone's\nUTXO at once. Poor Bob wants to both wait 60 seconds to see if a\nconflicting tx ends up in his mempool, *and* broadcast it ASAP to signal\nto others. He wants to do both of these *before* revealing his own\nUTXOs.\n\nNot sure how to square this, but I do prefer this approach over PoDLE.\n\nCheers,\nRusty.",
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