Donovan Young on Nostr: To see where this two-parameter freedom comes from in the 4-partite case, consider ...
To see where this two-parameter freedom comes from in the 4-partite case, consider the following "moves" that can be made on a given perfect matching:
We could take one edge from the \(p_1\), and another from the \(p_3\). (We have chosen these two because they are non-incident, i.e. the groups \(p_2,p_4,p_5,p_6\) are joined to the \(p_1\) through a vertex. We've also assumed \(p_1,p_3>0\)).
Now we imagine breaking the two chosen edges (somewhere in their middles) and rejoining them in another way: we can either produce an edge to add to \(p_4\) and one to add to \(p_2\), or, rejoining them differently, an edge to add to \(p_5\) and an edge to add to \(p_6\).
This is a two-parameter freedom which can be applied in general to any two non-incident edges in the perfect matching.
Published at
2024-12-30 18:26:46Event JSON
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"content": "To see where this two-parameter freedom comes from in the 4-partite case, consider the following \"moves\" that can be made on a given perfect matching:\n\nWe could take one edge from the \\(p_1\\), and another from the \\(p_3\\). (We have chosen these two because they are non-incident, i.e. the groups \\(p_2,p_4,p_5,p_6\\) are joined to the \\(p_1\\) through a vertex. We've also assumed \\(p_1,p_3\u003e0\\)). \n\nNow we imagine breaking the two chosen edges (somewhere in their middles) and rejoining them in another way: we can either produce an edge to add to \\(p_4\\) and one to add to \\(p_2\\), or, rejoining them differently, an edge to add to \\(p_5\\) and an edge to add to \\(p_6\\). \n\nThis is a two-parameter freedom which can be applied in general to any two non-incident edges in the perfect matching.",
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