Oliver Egginger [ARCHIVE] on Nostr: 📅 Original date posted:2015-06-01 📝 Original message:On Mon, Jun 1, 2015 at ...
📅 Original date posted:2015-06-01
📝 Original message:On Mon, Jun 1, 2015 at 3:59 PM, Gavin Andresen wrote:
> What do other people think? Would starting at a max of 8 or 4 get
> consensus? Scaling up a little less than Nielsen's Law of Internet
> Bandwidth predicts for the next 20 years? (I think predictability is
> REALLY important).
>
> I chose 20 because all of my testing shows it to be safe, and all of my
> back-of-the-envelope calculations indicate the costs are reasonable.
>
> If consensus is "8 because more than order-of-magnitude increases are
> scary" -- ok.
It would feel better for me if you would keep the power of two:
2^0 = 1MB
2^1 = 2MB
2^2 = 4MB
2^3 = 8MB
.
.
.
But that's only personal. Maybe other people feeling the same.
- oliver
Published at
2023-06-07 15:36:06Event JSON
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"content": "📅 Original date posted:2015-06-01\n📝 Original message:On Mon, Jun 1, 2015 at 3:59 PM, Gavin Andresen wrote:\n\u003e What do other people think? Would starting at a max of 8 or 4 get\n\u003e consensus? Scaling up a little less than Nielsen's Law of Internet\n\u003e Bandwidth predicts for the next 20 years? (I think predictability is\n\u003e REALLY important).\n\u003e \n\u003e I chose 20 because all of my testing shows it to be safe, and all of my\n\u003e back-of-the-envelope calculations indicate the costs are reasonable.\n\u003e \n\u003e If consensus is \"8 because more than order-of-magnitude increases are\n\u003e scary\" -- ok.\n\nIt would feel better for me if you would keep the power of two:\n\n2^0 = 1MB\n2^1 = 2MB\n2^2 = 4MB\n2^3 = 8MB\n.\n.\n.\n\nBut that's only personal. Maybe other people feeling the same.\n\n- oliver",
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