nprofile1qy2hwumn8ghj7un9d3shjtnddaehgu3wwp6kyqpq8ytv7sacr8rfz68ek35vdg38a2dp0mfgulq2a6rkr9gcsfetx9jsnqcas5 (nprofile…cas5) nprofile1qy2hwumn8ghj7un9d3shjtnddaehgu3wwp6kyqpquymv6nxuw87waks7y74ymjg273agsm0u8mpjxpdy0ln6ml5z6y8s24fqqu (nprofile…fqqu) nprofile1qy2hwumn8ghj7un9d3shjtnddaehgu3wwp6kyqpqz2qdmfzhs2uwg8kmsh37xavt2hq48gch63e787ggd3s6mt8waxgs6aq8c7 (nprofile…q8c7) There are plenty of solutions to just 𝑎²+𝑏²=…=𝑀² -- the tricky thing is getting those extra two conditions to hold as well.
(Solving the equations without the extra two conditions basically comes down to finding numbers with "enough" factors in the so-called Gaussian integers, things of the form a + ib where i^2 = -1. Any time you have (𝑎+𝑖𝑏)(𝑎−𝑖𝑏)=𝑀² you also have 𝑎²+𝑏²=𝑀² . It's possible to get many many such factors, i.e., for that circle to have lots of rational points on it. But it's more difficult when we have the extra constraints relating those different (a,b) pairs.)
gjm /
npub19y…8lqjq
2025-02-22 00:24:48
in reply to nevent1q…73kj
Author Public Key
npub19ym8s0u4ahcxwtu0qrhpnp0rnlamhem33qae82mmsgt47pjv05aqp8lqjqPublished at
2025-02-22 00:24:48Event JSON
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